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Capacitor Lab: Basics Open PhET simulation Capacitor Lab: Basics Use πΆ = π0 π΄ π πΆ2 1 π€ππ‘β π0 = 4ππ = 8.85 Γ 10β12 ππ2 π‘π ππππ’πππ‘π π‘βπ πππππππ‘ππππ πππ πππππππ π‘π π‘βπ value given by the simulation. π΄ = 200ππ2 1.00π 2 (1.00π2 ) 200ππ2 (1000ππ) = 200ππ2 1.00Γ106 ππ2 = 2.00 Γ 10β4 π2 π = 6.0 Γ 10β3 π πΆ= π0 π΄ π = πΆ2 )(2.00Γ10β4 π2 ) ππ2 6.0Γ10β3 π (8.85Γ10β12 = 2.95 Γ 10β13 πΉ β 0.30 Γ 10β12 πΉ = 0.30ππΉ Leave the area constant at 200ππ2 and decrease the separation between the plates to 3.0mm. Calculate the new capacitance. Does your calculated value agree with the value given by the simulation? Why would the capacitance increase with decreasing separation? (Recall that the capacitance represent the amount of charge a capacitor can store per volt.) Once again leave the area constant at 200ππ2 and this time increase the separation between the plates to 9.0mm. Calculate the new capacitance. With increasing separation, the capacitance decreased. Why is this. Set the plate separation back to 6.0mm. Click on βTop Plate Chargeβ and βElectric Fieldβ. Set the battery voltage to 1.5V (all the way to the top). What charge is stored on the top plate? Note the number of electric field lines. Change the plate separation to 3.0mm. What charge is stored on the top plate? Did the number of electric field lines increase or decrease? Change the plate separation to 9.0mm. What charge is stored on the top plate? Did the number of electric field lines increase or decrease? Plate Separation (mm) Capacitance (pF) Charge (pC) 3 6 9 Set the plate separation back to 6.0mm. Keep the voltage at 1.5V. What is the capacitance and the charge on the top plate (recall that the charge on the bottom plate is equal in magnitude but of opposite sign). Vary the plate area from 100ππ2 to 300ππ2 and record the capacitance and the charge. Plate area (mm2) Capacitance (pF) Charge (pC) 100 200 300 What is the relationship between the area of the plates and the capacitance and the area of the plates and the charge? Use the multimeter (as a voltmeter) to measure the voltage across the capacitor. Vary the voltage from 0.00 volts to 1.50 V in increments of 0.100 V. Record the capacitance and the charge in the table below. Battery Voltage (V) 0.000 0.100 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.00 1.10 1.20 1.30 1.40 1.50 Capacitance (pF) Charge (pC) The capacitance did not change. Why did the capacitance not change? (Recall: πΆ = π0 π΄ ) π What is the relationship between the charge on the plates and the voltage supplied? Recall π = πΆπ. So the charge on the capacitor is equal to the capacitance times the applied voltage. Calculate the expected charge at 0.300V, 0.900V and 1.20V. Battery Voltage (V) 0.300 0.900 1.20 Charge (pC) Capacitor Lab: Basics Open PhET simulation Capacitor Lab: Basics Capacitor Labai PHET with Eo = EA 1 Use C= = 8.85 x 10-12 C? d 471k to calulate the capacitance and compare to the value Nm given by the simulation. 200mm?(1000mm) A = 200mm 1.00m 2 (1.00m) = 200mm? 2 1.00 x 10 mm = 2.00 Γ 10 -4m2 d= 6.0 X 10 -3m (8.85 % 8.85 x 10-12 x 10m) Nm = 2.95 x 10-13F 20.30 x 10-12 F = 0.30pF 6.0 x 10-3m 9-12 )(2.0 x EA C= d Leave the area constant at 200mm? and decrease the separation between the plates to 3.0mm. Calculate the new capacitance. Does your calculated value agree with the value given by the simulation? Why would the capacitance increase with decreasing separation? (Recall that the capacitance represent the amount of charge a capacitor can store per volt.) Once again leave the area constant at 200mm? and this time increase the separation between the plates to 9.0mm. Calculate the new capacitance. With increasing separation, the capacitance decreased. Why is this. Set the plate separation back to 6.0mm. Click on “Top Plate Chargeβ and βElectric Fieldβ. ΰ¦¬ΰ§ΰ§°ΰ§° Capacitance Top Plate Charge Stored Energy 0.30 pF 0.44 PC 0.33 pJ Plate Charges Bar Graphs Electric Field Current Direction Set the battery voltage to 1.5V (all the way to the top). What charge is stored on the top plate? Note the number of electric field lines. Change the plate separation to 3.0mm. What charge is stored on the top plate? Did the number of electric field lines increase or decrease? Change the plate separation to 9.0mm. What charge is stored on the top plate? Did the number of electric field lines increase or decrease? Plate Separation (mm) Capacitance (PF) Charge (PC) 3 6 9 Set the plate separation back to 6.0mm. Keep the voltage at 1.5V. What is the capacitance and the charge on the top plate (recall that the charge on the bottom plate is equal in magnitude but of opposite sign). Vary the plate area from 100mm2 to 300mmand record the capacitance and the charge. Plate area (mm) Capacitance (PF) Charge (PC) 100 200 300 What is the relationship between the area of the plates and the capacitance and the area of the plates and the charge? Use the multimeter (as a voltmeter) to measure the voltage across the capacitor. 50 mm 21923 Voltage 0.2007 2 Vary the voltage from 0.00 volts to 1.50 V in increments of 0.100 V. Record the capacitance and the charge in the table below. Battery Voltage (V) Capacitance (PF) Charge (PC) 0.000 0.100 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.00 1.10 1.20 1.30 1.40 1.50 EA The capacitance did not change. Why did the capacitance not change? (Recall: C = EA What is the relationship between the charge on the plates and the voltage supplied? Recall Q = CV. So the charge on the capacitor is equal to the capacitance times the applied voltage. Calculate the expected charge at 0.300V, 0.900V and 1.20V. Charge (PC) Battery Voltage (V) 0.300 0.900 1.20

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